28b^2-68b-48=0

Solution for 28b^2-68b-48=0 equation:

28b^2-68b-48=0

a = 28; b = -68; c = -48;
Δ = b2-4ac
Δ = -682-4·28·(-48)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-100}{2*28}=\frac{-32}{56}
=-4/7
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+100}{2*28}=\frac{168}{56}
=3
$